2[d-(4d+16)+12]=2(d+4)

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Solution for 2[d-(4d+16)+12]=2(d+4) equation:


Simplifying
2[d + -1(4d + 16) + 12] = 2(d + 4)

Reorder the terms:
2[d + -1(16 + 4d) + 12] = 2(d + 4)
2[d + (16 * -1 + 4d * -1) + 12] = 2(d + 4)
2[d + (-16 + -4d) + 12] = 2(d + 4)

Reorder the terms:
2[-16 + 12 + d + -4d] = 2(d + 4)

Combine like terms: -16 + 12 = -4
2[-4 + d + -4d] = 2(d + 4)

Combine like terms: d + -4d = -3d
2[-4 + -3d] = 2(d + 4)
[-4 * 2 + -3d * 2] = 2(d + 4)
[-8 + -6d] = 2(d + 4)

Reorder the terms:
-8 + -6d = 2(4 + d)
-8 + -6d = (4 * 2 + d * 2)
-8 + -6d = (8 + 2d)

Solving
-8 + -6d = 8 + 2d

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-2d' to each side of the equation.
-8 + -6d + -2d = 8 + 2d + -2d

Combine like terms: -6d + -2d = -8d
-8 + -8d = 8 + 2d + -2d

Combine like terms: 2d + -2d = 0
-8 + -8d = 8 + 0
-8 + -8d = 8

Add '8' to each side of the equation.
-8 + 8 + -8d = 8 + 8

Combine like terms: -8 + 8 = 0
0 + -8d = 8 + 8
-8d = 8 + 8

Combine like terms: 8 + 8 = 16
-8d = 16

Divide each side by '-8'.
d = -2

Simplifying
d = -2

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